Elementary Principles 104 - 4.71 a. 12 L CH 3 OH 1000 ml...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
4- 63 4.71 a. h / OH CH mol 6 . 296 g 04 . 32 mol ml g 792 . 0 L ml 1000 h OH CH L 12 3 3 = CH 3 OH + 3/2 O 2 CO 2 +2 H 2 O, CH 3 OH + O 2 CO +2 H 2 O 296.6 mol CH 3 OH(l)/h ± ( n 2 mol dry gas / h) 0.0045 mol CH 3 OH(v)/mol DG 0.0903 mol CO 2 /mol DG ± / n 1 (mol O h) 2 0.0181 mol CO/mol DG 376 1 . ± / n (mol N h) 2 x (mol N 2 /mol DG) (0.8871– x ) (mol O 2 /mol DG) ± ( n 3 mol H O(v) / h) 2 4 unknowns ( ± , ± , ± ,) nnnx 123 – 4 balances (C, H, O, N 2 ) = 0 D.F. b. Theoretical O 2 : 296.6 (1.5) = 444.9 mol O 2 / h C balance: 296.6 = ± n 2 (0.0045 + 0.0903 + 0.0181) ± n 2 = 2627 mol/h H balance: 4 (296.6) = ± n 2 (4*0.0045) + 2 ± n 3 ± n 3 = 569.6 mol H 2 O / h 69.6 5 x)] - 2(0.8871 .0181 0 2(0.0903) 627[0.0045 2 1 n 2 296.6 : balance O + + + + = + N 2 balance: 3.76 ± n 1 = x ( 2627) Solving simultaneously ± ./ / nx 1 574 3 = mol O h, = 0.822 mol N mol DG 22 Fractional conversion : fed react/mol OH CH mol 960 . 0 6 . 296 ) 0045 . 0 ( 2627 6 . 296 3 = % excess air : % 1 . 29 % 100 9 . 444 9 .
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.
Ask a homework question - tutors are online