Elementary Principles 98 - 4.64 a. Basis: 1000 g gas...

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4- 57 4.64 a. Basis : 1000 g gas Species m (g) MW n (mol) mole % (wet) mole % (dry) C 3 H 8 800 44.09 18.145 77.2% 87.5% C 4 H 10 150 58.12 2.581 11.0% 12.5% H 2 O 50 18.02 2.775 11.8% Total 1000 23.501 100% 100% Total moles = 23.50 mol, Total moles (dry) = 20.74 mol Ratio : 2.775 / 20.726 = 0.134 mol H O / mol dry gas 2 b. C 3 H 8 + 5 O 2 3 CO 2 + 4 H 2 O, C 4 H 10 + 13/2 O 2 4 CO 2 + 5 H 2 O Theoretical O 2 : CH 100 kg gas h 80 kg C H 100 kg gas 1 kmol C H 44.09 kg C H 5 kmol O 1 kmol C H 9.07 kmol O / h 38 2 2 : = 100 kg gas h 15 kg C H 100 kg gas 58.12 kg C H 6.5 kmol O 1 kmol C H 1.68 kmol O / h 41 0 0 0 0 2 0 2 : = Total : (9.07 + 1.68) kmol O 2 /h = 10.75 kmol O 2 /h Air feed rate : 10.75 kmol O h 1 kmol Air .21 kmol O 1.3 kmol air fed 1 kmol air required 66.5 kmol air / h 2 2 = The answer does not change for incomplete combustion
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