Elementary Principles 89 - 4.56 a. 900 kg HCHO 1 kmol HCHO...

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4- 48 4.56 a. 900 1 30 03 30 0 kg HCHO kmol HCHO kg HCHO kmol HCHO / h h . . = n 1 (kmol CH 3 OH / h) 30.0 kmol HCHO / h (kmol H 2 /h) (kmol CH 3 OH / h) 2 3 n n % conversion : 30 0 060 500 1 1 . .. n n =⇒ = kmol CH OH / h 3 b. n 1 (kmol CH 3 OH / h) 30.0 kmol HCHO / h 2 (kmol H 2 3 (kmol CH 3 OH /h) n n 30.0 kmol HCHO / h 2 (kmol H 2 n n 3 (kmol CH 3 OH / h) Overall C balance : n 1 (1) = 30.0 (1) n 1 = 30.0 kmol CH 3 OH/h (fresh feed) Single pass conversion : 30 0 13 3 20 0 . nn n + = kmol CH 3 OH / h n 1 + n 3 = 50.0 kmol CH 3 OH fed to reactor/h c. Increased x sp will (1) require a larger reactor and so will increase the cost of the reactor and (2) lower the quantities of unreacted methanol and so will decrease the cost of the
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This note was uploaded on 02/27/2012 for the course CHEMICAL E 312 taught by Professor Cheung during the Fall '11 term at The University of Akron.

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