Elementary Principles 83 - 4.51 (cont'd) b. (1) n1 = 46.08...

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4- 42 4.51 (cont'd) b. (1) 46.08 mol C H (3) 47.4 mol H O (4) 9.3 mol I Reactor feed contains 44.8% C H , 46.1% H O, 9.1% I 12 6 22 3 26 2 ⇒= U V | W | n n n % conversion of C 2 H 4 : 46 08 433 46 08 100% 6 0% .. . . ×= If all C 2 H 4 were converted and the second reaction did not occur, n CHOH 25 46 08 di max . = mol Fractional Yield of C 2 H 5 OH : nn C H OH C H OH 2 5 46 08 0 054 /. / . . max bg == Selectivity of C 2 H 5 OH to (C 2 H 5 ) 2 O : 2.5 mol C H OH 0.14 mol (C H ) O 17.9 mol C H OH / mol (C H ) O 2 2 = c. Keep conversion low to prevent C 2 H 5 OH from being in reactor long enough to form significant amounts of (C 2 H 5 ) 2 O. Separate and recycle unreacted C 2 H 4 . 4.52 CaF s H SO l CaSO s 2HF g 4 4 b g +→+ 1 metric ton acid 1000 kg acid 0.60 kg HF 1 metric ton acid 1 kg acid kg HF = 600 Basis: 100 kg Ore dissolved (not fed)
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