Elementary Principles 75 - 4.43 (cont'd) O 2 : n3 = 0.21...

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4- 34 4.43 (cont’d) O m o l O N m o l N Cl mol Cl HO m o l HO 22 :. . . . n n n n 3 4 5 6 0211607 1 2 125 079 1607 127 425 =− = == bg ξ These molar quantities are the same as in part (a), so the mole fractions would also be the same. c. Use of pure O 2 would eliminate the need for an extra process to remove the N 2 from the product gas, but O 2 costs much more than air. The cheaper process will be the process of choice. 4.44 FeTiO 2H SO TiO SO FeSO 2H O Fe O 3H SO Fe SO H O TiO SO 2H O H TiO s H SO H TiO s TiO s H O 32 4 4 42 23 2 4 2 4 3 2 2 3 2 4 2 2 +→ + + + + →+ b g 3 Basis : 1000 kg TiO 2 produced 1000 kg TiO kmol TiO 1 kmol FeTiO 79.90 kg TiO 1 kmol TiO kmol FeTiO decomposes 3 3 = 1252 . 12.52 kmol FeTiO dec. 1 kmol FeTiO feed 0.89 kmol FeTiO dec. kmol FeTiO fed 33 3 3 = 1406 . 14.06 kmol FeTiO 1 kmol Ti 47.90 kg Ti 1 kmol FeTiO kmol Ti kg Ti fed 3 3 = 6735 . 0243 2772 .. kg Ti / kg ore kg ore fed MM =⇒ = Ore is made up entirely of 14.06 kmol FeTiO
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This note was uploaded on 02/27/2012 for the course CHEMICAL E 312 taught by Professor Cheung during the Fall '11 term at The University of Akron.

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