Elementary Principles 59 - 4.29 a. 100 mol / h 0.300 mol B...

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4- 18 4.29 a. 100 0300 0 250 0 450 mol / h molB / mol molT / mol molX / mol . . . ± n x x xx B T BT 2 2 2 22 1 mol / h molB / mol molT / mol molX / mol bg −− ± . . n 4 0940 0 060 mol / h molB / mol molT / mol ± . . n 3 0 020 0980 mol / h molT / mol molX / mol ± n x x B T 5 5 5 55 1 mol / h molB / mol molT / mol molX / mol Column 1 Column 2 Column 1 Column 2 : 4 unknowns ( ± , ± ,, nnx x 23 2 2 ) 4 unknowns ( ± , ± , ± , nnny x 345 ) –3 balances – 3 balances – 1 recovery of X in bot. (96%) – 1 recovery of B in top (97%) 0 DF 0 DF Column 1 96% X recovery : 096 0450 100 098 3 .. . ± b g = n (1) Total mole balance : 100 23 = + ±± nn (2) B balance : 0300 100 . ± = xn B ( 3 ) T balance : 0250 100 0 020 3 . ± . ± =+ n T (4) Column 2 97% B recovery : 097 4 . ± . ± n B = (5) Total mole balance : ±±± nnn 245 = + (6) B balance : n xn
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This note was uploaded on 02/27/2012 for the course CHEMICAL E 312 taught by Professor Cheung during the Fall '11 term at The University of Akron.

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