Elementary Principles 55 - 4.24 a n1 kmol min b g n3 kmol...

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4- 14 4.24 a. ± . n 1 200 kmol / min kgCO / min 2 bg ± . n 2 0015 kmol / min kmolCO / kmol 2 ± . n 3 0023 kmol / min kmolCO / kmol 2 ± . min . . n 1 20 0 44 0 0455 == kgCO kmol kmolCO / min 2 2 2 Overall balance : 0455 23 . ±± + = nn ( 1 ) CO 2 balance : 0455 0015 .. ± . ± + = ( 2 ) Solve (1) and (2) simultaneously = = ± ., ± . 556 561 kmol / min kmol / min b. u 150 18 833 m s m/s . AD D = 1 4 561 0123 1 60 108 2 π . min . min . . kmol m kmol s s m m 3 4.25 Spectrophotometer calibration : Ck A C A A C = ====> = = = 0.9 3 3333 g/L μ . Dye concentration : AC =⇒ = = 018 3333 018 0 600 . . b g Dye injected 0.60 cm L 5.0 mg 10 g 10 cm L 1 mg g 33 1 1 30 ⇒=
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This note was uploaded on 02/27/2012 for the course CHEMICAL E 312 taught by Professor Cheung during the Fall '11 term at The University of Akron.

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