4- 134.22 (cont’d) b. ±±.nmPP=22813Overall balance: ±±±.nnmABP+=H2balance: xnxmAABBPP±.⇒=−−=−−±±.±±.nmxxnmAPBPBABPPA2281322813bgc. TrialXAXBXPmPnAnB10.100.5.101004.380.0020.1.5.201003.291.1030.1.5.301002.192.1922.214.171.1241001.1.29126.96.36.19910.0.38188.8.131.52100-1.105.4870.100.500.1025010.960.00.1.5.202508.222.74184.108.40.20625.485.48100.100.500.402502.748.22110.100.500.502500.0010.96120.100.500.60250-2.7413.70The results of trials 6 and 12 are impossible since the flow rates are negative. You cannot blend a 10% H2mixture with a 50% H2mixture and obtain a 60% H2mixture. d. Results are the same as in part c. 4.23 Arterialbloodml / minmg urea / ml200 0190..Dialyzing fluid1500Venous bloodmg urea/ml1950175..Dialysate/ml±vca. Water removal rate
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This note was uploaded on 02/27/2012 for the course CHEMICAL E 312 taught by Professor Cheung during the Fall '11 term at The University of Akron.