Elementary Principles 52 - 4.19 (cont'd) Assume volume...

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4- 11 4.19 (cont’d) Assume volume additivity : mm 13 1000 400 7440 1480 kg m kg kg m kg kg m kg 33 3 bg += (2) Solve (1) and (2) simultaneously = = 668 1068 kgH O kgsuspension 2 , v 1 668 1000 0668 == kg m kg m waterfed totank 3 3 . b. Specific gravity of coal < 1.48 < Specific gravity of slate c. The suspension begins to settle. Stir the suspension. 1.00 < Specific gravity of coal < 1.48 4.20 a. ± . . n 1 0040 0960 mol / h molH O / mol mol DA / mol 2 ± n x x 2 1 mol / h molH O / mol mol DA / mol 2 ± n 3 97% molH Oadsorbed / h of H Oin feed 2 2 Adsorption rate : ± .. . . n 3 354 340 0 0180 1556 = = kg 5 h molH O molH O / h 2 2 2 97% adsorbed : 156 097 004 401 11 . ±± . =⇒ = nn mol / h Total mole balance : ±±± ± . nnn n 123 2 401 1556 3854 = + = = mol / h Water balance : () ( )( ) 3 2 0.040 40.1 1.556 38.54 1.2 10 molH O/mol
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This note was uploaded on 02/27/2012 for the course CHEMICAL E 312 taught by Professor Cheung during the Fall '11 term at The University of Akron.

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