Elementary Principles 51 - 4.18 a. 100 kg 0.800 kgS / kg...

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4- 10 4.18 a. 100 0800 0200 kg kgS / kg kgH O / kg 2 . . m m 2 3 kgS kgH O 2 b g b g m 1 kgH O 85%of enteringwater 2 bg b g 85% drying : m 1 0850 0 200 100 17 0 == .. . b g 2 Sugar balance : m 2 0800100 800 kgS Overall balance : 100 17 80 3 33 = + + = mm 2 x w = + = 3 38 0 00361 kg kgH O / kg 2 2 . m 1 23 17 80 3 0205 + = + = kg kgH O / kgwetsugar 2 2 b. 1000 3 100 30 tonswet sugar day tonsH O tonswet sugar tons H O / day 2 2 = 1000 2000 15 365 81 0 7 tonsWS day tonsDS tonWS lb ton lb days year per year m m .$ 0 . $8. c. xx x x x x ww w w w w =+ + + = =− + + = 1 10 0 0504 1 9 0 00181 00504 3 0 00181 0 0450 0 0558 12 1 0 1 2 10 2 ... . . ., . b g kg H O / kg SD kg H O / kg Endpoints Lower limit Upper limit 2 2 d. The evaporator is probably not working according to design specifications since
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