Elementary Principles 48 - 4.13 (cont'd) b. Effluent: x =...

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4- 7 4.13 (cont’d) b. Effluent : x p == 0 000145 388 0494 13645 .. . bg kgP / kg Product : x p 0 000145 583 0861 13645 . Waste : x p 0 000145 140 0123 . Efficiency = 0861 1239 0 494 2253 100% 958% . . . c. Mass balance on purifier : 2253 1239 1014 = + = mm ww kg P balance on purifier : Input : 0494 2253 1113 . kgP / kg kg kgP b g = Output : 0861 1239 0123 1014 1192 kgP / kg kg kgP / kg kg b g b g += The P balance does not close . Analyzer readings are wrong; impure feed; extrapolation beyond analyzer calibration data is risky -- recalibrate; get data for R > 583; not at steady state; additional reaction occurs in purifier; normal data scatter. 4.14 a. ± . . n 1 00100 09900 lb- mole/ h lb- mole H O/ lb- mole lb- mole DA/ lb- mole 2 b g ± ± n v 2 2 lb- mole HO/ h ft / h 2 3 b g d i ± . . n 3 0100 0900 lb- mole/ h 2 b g 4 unknowns ( ± , ± , ± , ± nnnv 123 ) – 2 balances – 1 density – 1 meter reading = 0 DF Assume linear relationship: ± v aR b
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This note was uploaded on 02/27/2012 for the course CHEMICAL E 312 taught by Professor Cheung during the Fall '11 term at The University of Akron.

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