Elementary Principles 18

Elementary Principles 18 - 3.3(cont'd(d Assuming that 1 cm3...

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Unformatted text preview: 3.3 (cont'd) (d) Assuming that 1 cm3 kerosene was mixed with Vg (cm3 ) gasoline Vg cm3gasoline 0.70Vg g gasoline 3 i d i 1dcm kerosenei 0.82dg kerosenei d0.70V + 0.82idg blendi = 0.78 V SG = V + 1dcm blend i g d 3 g = g 0.82 - 0.78 3 = 0.5 0 cm 0.78 - 0.70 Volumetric ratio = 50.0 kg Vgasoline 0.50 cm3 3 3 = 3 = 0.50 cm gasoline / cm kerosene Vkerosene 1 cm 3.4 In France: In U.S.: L 5 Fr \$1 = \$68.42 0.7 10 kg 1L 5.22 Fr . 50.0 kg L 1 gal \$1.20 = \$22.64 0.70 10 kg 3.7854 L 1 gal . 3.5 V B ( ft 3 / h ), m B ( lb m / h ) V ( ft 3 / h), SG = 0.850 V H ( ft 3 / h ), m H ( lb m / h ) 700 lb m / h (a) V = 700 lb m h VB ft 3 ft 3 0.850 62.43 lb m = 1319 ft 3 / h . mB = mH d i 0.879 62.43 lb = 54.88V bkg / hg ft b hg = dV hb0.659 62.43g = 4114V b kg / hg . m 3 B H H 3 VB + VH = 1319 ft / h . mB + mH = 54.88VB + 4114VH = 700 lb m . VB = 114 ft 3 / h mB = 628 lb m / h benzene . VH = 1.74 ft 3 / h mH = 71.6 lb m / h hexane (b) No buildup of mass in unit. B and H at inlet stream conditions are equal to their tabulated values (which are strictly valid at 20 C and 1 atm.) Volumes of benzene and hexane are additive. Densitometer gives correct reading. o 3-2 ...
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This note was uploaded on 02/27/2012 for the course CHEMICAL E 312 taught by Professor Cheung during the Fall '11 term at The University of Akron.

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