Elementary Principles 1 - CHAPTER TWO 2.1 (a) = 18144 10 9...

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2- 1 CHAPTER TWO 2.1 (a) 3 24 3600 1 18144 10 9 wk 7 d h s 1000 ms 1 wk 1 d h 1 s ms . (b) 38 3600 2598 26 0 . .. 1 ft / s 0.0006214 mi s 3.2808 ft 1 h mi / h mi / h =⇒ (c) 554 1 1 1000 g 3 m 1 d h kg 10 cm d kg 24 h 60 min 1 m 85 10 cm g 48 4 4 44 ./ m i n 2.2 (a) 760 mi 3600 340 1 m 1 h h 0.0006214 mi s m/s = (b) 921 kg 35.3145 ft 57 5 2.20462 lb 1 m m 1 kg lb / ft m 3 33 m 3 = . (c) 537 10 1000 J 1 1 119 93 120 3 . . ×× kJ 1 min .34 10 hp min 60 s 1 kJ J / s hp hp -3 2.3 Assume that a golf ball occupies the space equivalent to a 222 in in in × × cube. For a classroom with dimensions 40 40 15 ft ft ft × × : n balls 6 ft (12) in 1 ball ft in 10 5 million balls = =×≈ 40 40 15 2 518 3 3 . The estimate could vary by an order of magnitude or more, depending on the assumptions made. 2.4 4 3 24 3600 s 1 0 0006214 . . light yr 365 d h
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This note was uploaded on 02/27/2012 for the course CHEMICAL E 312 taught by Professor Cheung during the Fall '11 term at The University of Akron.

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