CN2010 Membrane Physiology Problem set 1 Key

# CN2010 Membrane Physiology Problem set 1 Key - Problem 1...

This preview shows pages 1–2. Sign up to view the full content.

Problem 1 Axon ion movements The squid axon has a specific membrane capacitance of 10 -6 Farads/cm 2 . The membrane potential is -60 mV at rest and +40 mV at the peak of the action potential. When the membrane potential changes, the charge on the membrane capacitance changes. A. 1. How many Na + ions must enter the axon per square centimeter of axon membrane to change the charge from the resting potential to the peak action potential? The change in potential from rest to peak is +100 mV. Q=C V = 10 -6 Farads x 0.1V = 10 -7 coulombs. The Faraday constant is 9.65x10 4 C/mole, Avogadro's constant is 6.03x10 23 molecules/mole. ions = (10 -7 coulomb)/(9.65x10 4 C/mole)x(6.03x10 23 molecules/mole) = 6.24 x 10 11 ions per cm 2 2. How many K + ions must leave to return the potential to rest? the same B. 1. For an axon which is 400 μm in diameter, what is the surface area of a 1 cm length of axon? Surface per cm length: 0.126 cm 2 2. How many Na + ions must enter the axon per centimeter of axon length to change the charge from the resting potential to the peak action potential? Ions per cm length: (0.126 cm 2 ) x (6.24 x 10 11 ions per cm 2 ) = 7.84 x 10 10 ions per cm 3. How many K + ions must leave to return the potential to rest? the same C. 1. For an axon which is 400 μm in diameter, what is the volume of a 1 cm length of axon? Volume per cm length: 1.26x10 -3 cm 3 per cm (or 1.26 x 10 -6 l per cm) 2. The intracellular ion concentrations for the squid axon are [Na + ] = 55 mM and [K + ] = 410 mM. What changes in the internal ion concentrations for Na + and K + occur during an action potential if the only ion movement is to charge and discharge the membrane capacitance? Na + entry: (7.84 x 10 10 ions per cm) / (6.03x10 23 molecules/mole) / (1.26 x10 -6 l per cm) = 1.04 x 10 -7 M per action potential. So fractional change is (1.04 x 10 -7 M) / (5.5 x 10 -2 M) = 1.88 x 10 -6 K + exit is the same in terms of moles, and fractional change is (1.04 x 10 -7 M) / (4.1 x 10 -1 M) = 9.42 x 10 -7 D.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern