ECE111_2010SPRING_HW3_PROFSOLN_[0]

ECE111_2010SPRING_HW3_PROFSOLN_[0] - The Cooper Union...

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The Cooper Union Department of Electrical Engineering Solution Key Spring 2010 h = f 2 ; 6 ; 7 ; 3 g where the underscore denotes n = 0 . (a) Express h ( n ) as a superposition of impulses. h ( n ) = 2 ( n ) 6 ( n 1) + 7 ( n 2) + 3 ( n 3) (b) Write a di/erence equation with input x , output y . y ( n ) = 2 x ( n ) 6 x ( n 1) + 7 x ( n 2) + 3 x ( n 3) see attached (d) Write explicit formulas for H ( z ) and H ( ! ) . H ( z ) = 2 6 z 1 + 7 z 2 + 3 z 3 H ( ! ) = 2 6 e j! + 7 e j 2 ! + 3 e j 3 ! H ( z ) be the transfer function of a 6 th H ( z ) = 0 at 0 : 9 e ± j 2 3 , 0 : 8 e 4 and a double zero at z = 1 . Also, H ( z ) is scaled (multiplied by a constant factor) so that its DC gain is
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This note was uploaded on 02/27/2012 for the course CHEMISTRY/ CH/ECE/PH/ taught by Professor Faculty during the Spring '08 term at Cooper Union.

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ECE111_2010SPRING_HW3_PROFSOLN_[0] - The Cooper Union...

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