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ch6&ch7答案

ch6&ch7ç­”æ&iexcl...

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6-4 解: 1 0 0 ( ) ( ) ( ) T i S t S S T t d τ τ τ = − + 0 t T < < 0 0 2 2 2 2 2 sin sin ( ) 2 2 cos sin 2 4 2 cos 2 t n n S a a T t d T T a nt a nt t T n T a nt t T π π τ τ τ π π π π = = + 2 T t T < < 2 0 2 ( ) (2 )cos 2 a n S t T t T t π = 图可参见 6 11 2 2 0 1 ( ) 2 S T a T = 0 ( ) 4 T S T n = 0 2 0 1 ( ) ( ) 2 2 2 T T S T a T n n = − 3 2 n T π ω = 1 2 d nd T ω π = 1 2 d d n T ω π = 所以 n 越大 1/T 精度要求越高。 6-5 解: 1 0 2 ( ) ( ) 2 m T A t h t S T t T A t T < = = 2 3 2 0 2 ( ) ( ) (2 1) 2 T j ft m m j ft j ft H f h f e dt A e e j f π π π π = = 2 2 2 0 2 0 2 (3 2 ) 2 ( ) 3 (4 3 ) 2 3 (2 ) 2 2 0 T A t t T A t T t T S t T A T t T t T A T t t T else = < < < 图略。 4
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