Lesson%2018%20HW%20handout

Lesson%2018%20HW%20handout - A ( 3, - 1 ) and perpendicular...

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MA153 JIN NOTE for HW 18 6. Find an equation of the line passing through with slope . (Solution) Use a point-intercept form . Now multiply (denominator of slope). Then 7. Find a general form of an equation of the line through the points A ( 2, - 2 ) and B ( - 2, 5 ). (Solution) The slope of the line which passes through is Now we can use a point-intercept form Multiply 4(denominator of slope). Then 8. Find a general form of an equation of the line that satisfies the given conditions. Through ; parallel to the line . (Solution) The slope of the desired line is same as one of . Hence the slope is . Now we a the point-slope form. 9. Find a general form of an equation of the line through the point
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Unformatted text preview: A ( 3, - 1 ) and perpendicular to the line 2 x- 3 y = 2. (Solution) The given line is Since the slope of this line is , the slope of the desired line is (take inverse and multiply it by -1). Use a point-slope form of a line equation to get 10. Find the slope-intercept form of the line with the x-intercept 11 and y-intercept - 4. 11-4 (Solution) The slope is . Definitely, the y-intercept is . Hence the slope-intercept form is . 11. Find the slope-intercept form of the line through the points A (2, 3) and B ( - 1, 4). (Solution) The slope is . Note that we are asked to find the slope-intercept form. Hence we apply a point-slope form to get...
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This document was uploaded on 02/26/2012.

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