ch10 lec exams solutions

# ch10 lec exams solutions - 6 Arrange the following liquids...

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CHM 11200 Spring 10 Chapter 10 Worked Lecture Examples

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Example 1 (Practice Problem 10.1, p 380) 2 normal b.p. occurs when vapor pressure equals 1 atm (~ 43°C) b.p. at 0.40 atm ~ 62°C
Example 2 (Practice Problem 10.2, p 382) 3 gas solid gas solid is deposition deposition is endothermic

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Example 3 (Practice Problem 10.4, p 387) 4 Calculate the heat absorbed when 125 g of water at 72.0°C is converted to steam at 186.4°C. The specific heat of water is 4.18 J/(g °C), the heat of vaporization of water is 4.07 x 10 4 J/mol, and the specific heat of steam is 2.02 J/(g °C) 72.0°C water 100.0°C water 100.0°C steam 186.4°C steam heat heat vaporize ( ) O H mol 6.939 g 18.0152 mol 1 O H g 125 2 2 = ! ! " # \$ \$ % &
Example 3 (cont’d) 5 ( ) ( ) ( ) ( ) ( ) J 21816 C 100 - C 186.4 C g J 2.02 g 125 q J 282417.3 mol J 10 4.07 mol 6.939 q J 14630 C 72 - C 100 C g J 4.18 g 125 q steam heat 4 water boil water heat = ! ! " # \$ \$ % & ' = = ! ! " # \$ \$ % & ( = = ! ! " # \$ \$ % & ' = o o o o o o q total = q heat water + q boil water + q heat steam q total = 14630 J + 282417.3 J + 21816 J = 318863.3 J q total = 3.19 × 10 5 J

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Example 4 (Practice Problem 10.9, p 396)
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Unformatted text preview: 6 Arrange the following liquids in order of increasing boiling points: CHBr 3 , CHCl 3 , CHI 3 CHCl 3 < CHBr 3 < CHI 3 The thing that is different about these is the halogen (Cl, Br, I). As the size of the halogen increases, the molar mass of the compound increases and the boiling point increases. Example 5 (Practice Problem 10.11, p 397) 7 Consider the substances CO and HF. Which has the stronger intermolecular forces? Which has the higher melting point? Boiling point? Vapor pressure? HF hydrogen bonds with itself. Therefore: HF has stronger intermolecular forces HF has the higher melting point (because of the stronger intermolecular forces). HF has the higher boiling point (because of the stronger intermolecular forces). CO has the higher vapor pressure (because it’s intermolecular forces are lower)....
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