Chapter%2011_Examples

# Chapter%2011_Examples - CHM 11200 Spring 10 Chapter 11...

This preview shows pages 1–5. Sign up to view the full content.

CHM 11200 Spring 10 Chapter 11 Worked Lecture Examples

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
Example 1 (Practice Problem 11.8, p 441) 2 When a solution of lead(II) nitrate is mixed with a solution of potassium chromate, a yellow precipitate forms according to the equation Pb(NO 3 ) 2 (aq) + K 2 CrO 4 (aq) PbCrO 4 (s) + 2 KNO 3 (aq) What volume of 0.105 M lead(II) nitrate is required to react with 100.0 mL of 0.120 M potassium chromate? What mass of PbCrO 4 solid forms? First, calculate the number of moles of K 2 CrO 4 : 0.1000 L ( ) 0.120 mol 1 L = 0.0120 mol K 2 CrO 4
Example 1 (cont’d) 3 First, calculate the number of moles of K 2 CrO 4 : 0.1000 L ( ) 0.120 mol 1 L = 0.0120 mol K 2 CrO 4 Next, calculate the number of moles of Pb(NO 3 ) 2 needed to react with the 0.0120 mol K 2 CrO 4 : mol Pb(NO 3 ) 2 = 0.0120 mol K 2 CrO 4 ( ) 1 mol Pb(NO 3 ) 2 1 mol K 2 CrO 4 = 0.0120 mol Pb(NO 3 ) 2 Next, calculate the volume of 0.105 M Pb(NO 3 ) 2 needed: 0.0120 mol Pb(NO 3 ) 2 1 L 0.105 mol = 0.114 L or 114 mL

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
Example 1 (cont’d)
This is the end of the preview. Sign up to access the rest of the document.

## Chapter%2011_Examples - CHM 11200 Spring 10 Chapter 11...

This preview shows document pages 1 - 5. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online