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Unformatted text preview: Version 028 Quiz 1 gentle (56245) 1 This printout should have 12 questions. Multiplechoice questions may continue on the next column or page find all choices before answering. 001 (part 1 of 2) 10.0 points A car initially at rest on a straight road accelerates according to the acceleration vs time plot. t a t 1 t 2 t 3 t 4 What is the best description of the motion of the car? Take forward to be the positive direction. 1. The car starts at rest, accelerates to a high speed, cruises for a short while, decelerates to a lower speed, then cruises. correct 2. The car goes forward and then goes back ward, ending behind where it started. 3. The car goes forward and then goes back ward, ending where it started. 4. The car starts at rest, accelerates to a low speed, comes to a stop, accelerates backwards and cruises in reverse. 5. The car starts at rest, goes up to a high speed, stops moving, travels backward, and stops. 6. The car goes backward and then goes forward. Explanation: Use the acceleration to determine the ve locity behavior: 1) v = 0 (initially at rest) 2) 0 < t < t 1 : a = 0 (remains at rest) 3) t 1 < t < t 2 : a > 0 (accelerates forward) 4) t 2 < t < t 3 : a = 0 (constant speed) 5) t 3 < t < t 4 : a < 0 (decelerates) 6) t 4 < t : a = 0 (constant speed) 002 (part 2 of 2) 10.0 points Which of the following graphs describes the velocity vs time of the car? 1. t v t 1 t 2 t 3 t 4 2. None of these graphs is correct. 3. t v t 1 t 2 t 3 t 4 4. t v t 1 t 2 t 3 t 4 correct 5. t v t 1 t 2 t 3 t 4 6. t v t 1 t 2 t 3 t 4 7. t v t 1 t 2 t 3 t 4 8. t v t 1 t 2 t 3 t 4 Version 028 Quiz 1 gentle (56245) 2 9. t v t 1 t 2 t 3 t 4 Explanation: 1) 0 < t < t 1 : v = 0 2) t 1 < t < t 2 : velocity increases uniformly 3) t 2 < t < t 3 : constant velocity 4) t 3 < t < t 4 : velocity decreases uniformly 5) t 4 < t : constant velocity The velocity vs time graph can be found by plotting the area under the acceleration vs time curve. 003 10.0 points A basketball player achieves a hang time of . 658 s in dunking the ball. What vertical height will he attain? The acceleration of gravity is 9 . 8 m / s 2 . 1. 0.396607 2. 1.50932 3. 1.11957 4. 1.62006 5. 1.73472 6. 0.636805 7. 0.59341 8. 0.530381 9. 0.563113 10. 1.225 Correct answer: 0 . 530381 m....
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This note was uploaded on 02/28/2012 for the course PHY 316 taught by Professor Markert during the Fall '10 term at University of Texas at Austin.
 Fall '10
 MARKERT
 mechanics

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