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Exam 1 Answer Sheet
1. PV=nRT
V=(nRT)/P
26.4 g O
2
x (1mol/32g O
2
) = 0.825 mol O
2
= n
R = 0.08206 L atm/mol K
T = 273.15 K
P = 1 atm
V
O2
= (0.825 mol O
2
x 0.08206 L atm/mol K x 273.15 K)/1 atm
V
O2
= 18.5 L
2V
O2
= V
CO2
= 37.0 L
n
CO2
= PV/RT = (1 atm x 37.0 L)/(0.08206 L atm/mol K x 273.15K)
n
CO2
= 1.65 mol CO
2
x (44g/mol) =
72.6 g CO
2
2. Ba(NO
3
)
2
0.450M
V = ?
NO
3

0.272M
V = 261.0 mL
0.450M Ba(NO
3
)
2
x (2 mol NO
3
/1 mol Ba(NO
3
)
2
) = 0.900 M NO
3
M
1
V
1
= M
2
V
2
(0.9M)V
1
= (0.272M)(261.0mL)
V
1
= 78.9 mL
3.
112
In
x
115
In
1x
114.8g = 112x + 115(1x)
114.8g = 112x + 115 – 115x
0.2g = 3x
x = 0.06 x 100% = 6%
10.06 = 0.94 x 100% = 94%
4.
NaCl – 4.0 M; 0.04L
CaCl
2
– 5.0M; 0.02L
M x L = mol
4M x 0.04L = 0.16 mol NaCl x (1 mol Cl/1 mol NaCl) = 0.16 mol Cl
5 M x 0.02 L = 0.1 mol Ca Cl
2
x (2 mol Cl/1 mol CaCl
2
) = 0.2 mol Cl
(0.16 mol + 0.2 mol)/(0.04 L + 0.02 L) =
6 M Cl
5.
C
6.
B
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View Full Document7. NaBrO
x
52.95% Br
52.95 g Br (assume 100g sample)
47.05% Na + O
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 Spring '08
 Any
 Physics, Work

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