ME530_L11_09_17_10

ME530_L11_09_17_10 - Name (m Mfr/59ft- htesstl...

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Unformatted text preview: Name (m Mfr/59ft- htesstl Mmed'l‘hermodynamics riot: “I? Heufixaml Hi, L. rs I. (35 pts) Steaminavertieal pistonendcyiinder arrangement isusedto lift emassthat is on flap of the piston. The piston cross-Sectional area is 0.1 m2 and the mass and piston together weigh 20 1:14“. The initial piston volume is 0.01 m3 and it is initially filled with matZOfl’C. fl-flfikgofsteamfi-omaresen'oiristhrottled into theoylindettoraise tbepistonto ilsfinalposition. The steaminthereservoir isaI4DU°C.TDDI-:Pa. The enviromnent around the piston. cylinder, and reaervoir is air at 20 “C. 100 kPa. at. e 745'? a alt-O l‘ (a) Calculate the final mass ofsteam in the piston and cylinder. f#—+ a“. (1:) Calculate the final temperature efthe steam in the piston and cylinder. {iii "‘3 (c) Calculate the total (throttle valve and pistonand eylhder) irrevem‘bility of this TB =10“; - II'\__ __ W' ______..—---—--"""'-_"lII F LN , H_ . ‘ S ' . 1 l . 54g: [.ah‘iiltlfillool‘} -(m3nlyrigugjugflsqugo) . 5L imp”! £15; . k "Hallm __.-._ ...... -.- 39f: O‘G'Zlgle'l "If 1- _ 1 if j: :TEESEJ.‘ 54: elofil HT 1 £6) H:U{_{3U’ . use 11.55 pts} Five ky'sec ersatu'bineat 1400K, moo kPa, and exitsat 950K, “1'3 100 kPa. The turbine pro -- 1800 kW nfpower. You can assume that any heat loss ' 1 ‘65 fium the turbine oeems at an average turbine surface temperature 0300 K. Kinetic and 4-453 potential energy changes can be neglected and the turbine is operating in steady state. The environment is at 300 11,100 kPa. {a} Calculate the heat loss from the turbine. {b} Identify and calculate all exergy fbws across the turbine boundary. (-3) Calculate the hmversibility of the turbine. éa . I ' ' _ . - d--- . J @J) ' - -_ “A (blah amines, - f -- “gm 8 Ch “flu-L.1+ 1.1.) (show-Er. “3—03 LI r #7th ._[S)LW3 (goeaggbmwf :) Ell { ("UNI 1]]. (30 pts) A 1.0 kg. 40 "C. block ofcopper is placed into 5.0 kg of“) C13 water. The water and copper as a system undergo a process that brings them into equilibrium with each other. Neglect kinetic and potential ermgy changes and assume there are no work or heat transfer interactions of the combined system with the environment. The system anderrvironmentpressuressreall 100 IrPa. The envnonmem temperamreiszs °C. (a}Calculatethefinaltemperatureofdie¢opperandmersystem 6k6‘6F9=’o [bJCaleulatetheE o ofthecopperandwstersystem. (c) Calculate the irreversr ility of the process. "3.1.110 a Q ’ wt :I: k'j Tc“: LU) C CIA a :3) MW 1 Ski], THU—"[0 L ._.. p: looerzcc~=+ Twas“ - (a) u WEE-fl? =7 Liz-U.” C“ "L '- _ —._I_ ) Cw; wet-om) New W _ T mean _ T = 53—51% * tqmras‘fimrstt) '30 :5 ~_ mmmfl‘w—'¢5’3*¢‘1€31-(m “D L m“ cméu u— E ,- get "sq / 9 = (333)¥(l.1o1¢t -o.nq7)hy — - la, M ___._———— El ; satisqfi 43112:: 4202 mg w» ...
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This note was uploaded on 02/28/2012 for the course ME 530 taught by Professor Ronnelson during the Fall '10 term at Iowa State.

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ME530_L11_09_17_10 - Name (m Mfr/59ft- htesstl...

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