ece524-s18

Ece524-s18 - mnm mNA g afizamzd Hz woémm m<m m2m mmmmSZ so 5 H c3m<mfimeO.—Qm_do Guzmanqozamro ECE 524 Session 18 Page THO Transients in

Info iconThis preview shows pages 1–13. Sign up to view the full content.

View Full Document Right Arrow Icon
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 2
Background image of page 3

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 4
Background image of page 5

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 6
Background image of page 7

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 8
Background image of page 9

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 10
Background image of page 11

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 12
Background image of page 13
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: mnm mNA g. afizamzd Hz woémm m<m+m2m mmmmSZ so. 5 H. c3m<mfimeO\.—Qm_do : _ _ Guzmanqozamro _ ECE 524: ' Session 18; Page THO Transients in Power Systems Spring 2012 ECE 524: Lecture 18 Three phase TRV transients MVAR :m iOOOkW My; 10‘ 6m 6M.» Consider the three phase system shown below: ' 12mm _‘ N51121: 2"”: 34.5w @ '- * = “a. 2 ma Sm" VLL I: 34.5kV Vm I: E-VLL Vm *"—’” 28.1710] ZS 2m 3-10—50hm 2 VLL QL := 12MVAR XL 2: XL a 99.199 QL XL 263 l H j: W E . m Lph 2-w-60Hz LP“ “ deMCIfiIL‘ CW 2: 2119 [Mei-M 1 1 1 fE1 :m fn = 6938.13“ 2m llfihcph 5 TH z: i Tn = 144.13us fn M Choose simuiation time step: T“ 48 --—- = . s 30 y” ca<mwmfi<oiam30 .\ .. ECE 524: Session 18; Page 2/10 Transients in Power Systems Spring 2012 Case 1: Zn :m ooohm Breaker currents 100 400 -200 0.00 0.02 0.04 0,06 0.08 [5] 0.10 (Hie Examplepw; xnvarn CIVSWA -LOAOA ctVSWf-l ALOADE! CIVSWC —LDADC Neutrai to ground voltage: 0.0 -'?’.5 -15.0 ~22.5 .N M '30}; 49.5 50.5 51.5 52.5 53.5 {ITS} 54.5 i (1 iie Example.plfi; xwv ar 1) v:N!EU ~ 509 W] 37.5 25.0 12.5 0.0 42.5 -25.0 -37.5 I500 0.00 0.02 0.0‘3 0.06 . [3? 0,10 (1 He Exampfiegfid: x—var I) v:LOA€)A ~NEU v:LOAOB NEU v:$._OADC -NEU Session 18; Page 6110 Spring 2012 ECE 524: Transients in Power Systems Case 3: Repeat with CT! :2 3-01,}. (In : 60F Iv WS'kcv Breaker currents: 300 25;“ 100 0 400 ~200 4500 0.00 0.02 0 .04 0.06 0.08 is; 0.10 (fife Exampiepmmwam) 01V5WA vLOADA c:V5WB -LOADB c:vswc -LOADC Neutral current afier first phase clears: 5.00 [A] 3.75 2.50 1.25 0.00 4.25 ~25!) 33.75 -5.00 49.0 50.6 50.2 50.4 50.6 50.8 51.0 51.2 ins; 51.4 We ExampteL17.pl4; x—var l) c:NEU - Neutrai current when ali phases clear: 5.00 [A] 3.75 2.50 ‘ 1.25 0.00 4.25 «2.50 -3.75 -5.00 53.5 53.8 54.1 54.4 54.7 imsi 55.0 (Ma ExampleL1?.p!4: xvvar l) c:NEU - ECE 524: Session 18; Page 8110 Transients in Power Systems Spring 2012 Breaker voltages: 20 —70 0.0330 0.0464 0.0598 0.0732 0.0866 {8} 01000 (file ExampéeL17.;)l4;x-vart)V:VSA -LOADA V:VSB -LOADB v:VSC -LGADC Arm: 78.846kV Case 4: high resistance grounci: Rgr I ph 1 chh m 1.33x106n chh := W 2-1T-60HZ'Cph W kg. :m 3.xcph Rgr ; 3.98MB 90 $le Wm 84.459kV 7° 50 Vmax Vm 2 3 30 10 ~10 -30 «50 -7‘0 - 0.0330 0.0464 0.0598 0.0732 0.0866 [3] 01000 (file Example£17.pl4; x-var l) ViVSA -LOADA v :VSB ~LOA08 v:VSC -LOADC ECE 524: Session 18; Page 9/10 Transients in Power Systems Spring 2012 Case 5: Add grounding resistance (high resistance ground——limit In to 20A): VLL Inmax :2 20A "Ram: Wfié Kg? 2 995.93 a use 1000 ohm nmax Breaker voltages: 18 -34 —60 0.0330 0.0464 0.0598 0.0732 0.0866 [5] 0.1000 (file ExampleL17.pi4;x-var£)VIVSA —LOA{)A v:VSB -L.0Af)B v:VSC -LOADC Case 6: Now try a low resistance ground (In 2 500A) 2mm? 500A 53%: “k Kg1r = 39.849 use 400m ' nmax 60 W: 56.771kV {:1 Vj: = 2.02 20 -2{} an} -60 0.0330 0.0464 0.0598 0.0732 0.0866 [5] 0.1000 (file ExampleL17.pM; x—var :} v:VSA -LOADA v:VSB ‘LOADB vzvsc -LOADC ...
View Full Document

This note was uploaded on 02/28/2012 for the course ECE 524 taught by Professor Staff during the Spring '08 term at Idaho.

Page1 / 13

Ece524-s18 - mnm mNA g afizamzd Hz woémm m<m m2m mmmmSZ so 5 H c3m<mfimeO.—Qm_do Guzmanqozamro ECE 524 Session 18 Page THO Transients in

This preview shows document pages 1 - 13. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online