ex61 - ECE 524: Transients in Power Systems Session 14;...

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ECE 524: Transients in Power Systems Session 14; Page 1/4 Spring 2012 ECE 524: Lecture 14 MVA 1000kW  MVAR MVA  pu 1  ω 2 π 60Hz ()  Example 6-1: Source impendance (convert to ohms on 13.8kV side of xfmr) V BLV 13.8kV  Z BLV V BLV 2 100MVA  Z S1_LV 0.002pu j 0.0286 pu Z BLV  Z S1_LV 0.0038 0.0545i Ω R S1_LV Re Z S1_LV   R S1_LV 0.0038 Ω L S1_LV Im Z S1_LV ω  L S1_LV 144.4751 μ H As an alternate approach, convert the per unit value to ohms on the HV side and the refer across the transformer. Both give the same results V BHV 138kV  Z BHV V BHV 2 100MVA  Z S1_HV 0.002pu j 0.0286 pu Z BHV  Z S1_HV 0.3809 5.4466i Ω Now we need to refer this to the LV side of the transformer: Z S1_LV_alt Z S1_HV 13.8 138 2  Z S1_LV_alt 0.0038 0.0545i Ω Not needed at the moment, but for completeness: Z S0_LV 0.0038pu j 0.0398 pu Z BLV  Z S0_LV 0.0072 0.0758i Ω
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ECE 524: Transients in Power Systems Session 14; Page 2/4 Spring 2012 Transformer Impedance Referred to 13.8kV):
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This note was uploaded on 02/28/2012 for the course ECE 524 taught by Professor Staff during the Spring '08 term at Idaho.

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ex61 - ECE 524: Transients in Power Systems Session 14;...

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