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–5[–3(7 – t) – 4(8 – 2t)] – 20 = –6[–2(6 – 3t) – 4]
Detailed Method
Eliminate the inner most parentheses by using the distributive
property, but first convert “minus 4” to “plus –4”…
–5[
(–3)
(
7 – t
)
+
(–4)
(
8 – 2t
)
] – 20 = –6[
(–2)
(
6 – 3t
)
– 4]
–5[
(–3)
7 –
(–3)
t +
(–4)
8 –
(–4)
2t] – 20 = –6[
(–2)
6 –
(–2)
3t – 4]
Simplify inside the innermost parentheses; multiplication only…
–5[–21
– (–3t) + (–32) – (–8t)
] – 20 = –6[–12
– (–6t)
– 4]
Simplify inside the innermost parentheses by converting “minus
–3 ” to “plus 3 ” and “plus –32” to “minus 32”, etc…
–3t” to “plus 3t” and “plus –32” to “minus 32”, etc…
–5[
–21
+ 3t
– 32
+ 8t
] – 20 = –6[
–12
+
6t – 4
]
Simplify inside the innermost parentheses by collecting like
terms…
–5[11t – 53] – 20 = –6[6t – 16]
Eliminate the inner most parentheses by using the distributive
property…
(–5)
11t –
(–5)
53 – 20 =
(–6)
6t –
(–6)
16
Simplify inside the innermost parentheses; multiplication only…
–55t – (–265) – 20 = –36t – (–96)
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View Full Document –55t
– (–265)
– 20 = –36t
– (–96)
Simplify by converting “minus –263” to “plus 263”, etc…
–55t + 265 – 20 = –36t + 96
Simplifying by collecting like terms…
–55t + 264 – 20 = –36t + 96
–55t + 245 = –36t + 96
Use the Additional and Multiplication principles to solve for x…
–55t + 245 = –36t + 96
+36t –245
+36t –245
–19
=
–149
–19t
–19t
–149
–19
–19
149
19
=
t =
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This note was uploaded on 02/29/2012 for the course MATH 120 taught by Professor Adjunct during the Fall '11 term at Northern Virginia Community College.
 Fall '11
 Adjunct
 Math

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