lab_22

# lab_22 - LAB 22 Specific Heat by Method of Mixtures...

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Unformatted text preview: LAB# 22 Specific Heat by Method of Mixtures Introduction: Placing a hot metal into a cup of cool water will cause the metal to cool and the water to increase in temperature. A final uniform temperature will be reached. Knowing the masses involved, the specific heat of water, and the temperatures involved will allow one to calculate the specific heat (C sample ) of the metal. For a perfectly insulated system, the change in the thermal energy of the system will be zero ( ∆ Q total = 0), and using Q = mC ∆ T, an equation can be derived to find C sample C : sample = - (m w C w + m cup C cup ) ( ∆ T w ) / (m sample ∆ T sample Where m ) w is the mass of the water, C w the specific heat of water (1 cal/g o C), m cup is the mass of the cup, C cup is the specific heat of the cup, ∆ T w is the change in temperature of the water, m sample is the mass of the sample metal, and ∆ T sample is the change in temperature of the sample metal. For this lab, all masses should be measured in grams and all temperatures should be measured in o Before the specific heat of the sample metal can be found, the specific heat of the cup must be determined. This will be done by using two samples of water held at different temperatures and then mixed together. Assuming another perfectly insulated system, ∆ Q = 0, and using Q = mC ∆ t, then C C....
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lab_22 - LAB 22 Specific Heat by Method of Mixtures...

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