# lab13 - LAB 13 Equilibrium of a Rigid Body Introduction The...

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LAB # 13 Equilibrium of a Rigid Body Introduction: The two conditions for a rigid body to be in equilibrium are: a. the resultant of all the forces acting on the body must equal zero: F i = 0 ! (1) b. the resultant of all the torque's acting on a body (computed around any axis) must equal zero. S i = 0 (2) As discussed in your textbook, a torque may be identified with the ability of a force to produce rotation. A torque depends on three factors: a. the magnitude of the force. b. the direction of the force. c. the point of application of the force on a rigid body relative to some axis of rotation. These factors may be combined in the equation: ! = F ( L sin " ) (3) where: τ = torque F = force L = vector from the axis of rotation to the point application of the force. θ = angle between F and L ( see Fig. 1). ` Thus the torque would take on its maximum value when θ = 90 ° so that sin θ = 1. It is convenient to regard a torque which would produce rotation in a counter-clockwise

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## This note was uploaded on 02/29/2012 for the course PHYS 227 taught by Professor Rabe during the Fall '08 term at Rutgers.

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lab13 - LAB 13 Equilibrium of a Rigid Body Introduction The...

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