thermo - Thermodynamics Objective: To investigate the...

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Thermodynamics Objective: To investigate the zeroth and first laws of thermodynamics. To calculate properties such as specific heat. To investigate the ideal gas law. To become familiar with basic P-V diagrams. Apparatus: Gas bulb, hot plate, hot water (from heating stainless steel bucket of water with hot plate), Pasco Gas Law piston, tubing, blue valve in tubing, temperature probe, pressure probe , tap water, styrofoam cup, metal block, scale, paper towels, ice (from cooler in Room 209 or ice machine in Room 210) , white plastic bucket (for transporting ice), ring stand, 100g or 200g mass. Theory: We can summarize the four laws of thermodynamics as follows: 0 th Law If you have two objects of the same temperature in physical contact with each other, they will exchange no heat and are said to be in thermal equilibrium . 1 st Law The change in energy of a system is equal to the heat gained by the system minus the work done by the system: U =Q W
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nd Law This law places constraints on the direction of the transfer of heat and efficiencies of heat engines. It also introduces the concept of entropy , a measure of the amount of disorder of a system, and states that only reversible processes result in the conservation of this quanity; irreversible processes are ones where this quantity always increases. 4 th Law You can approach absolute zero arbitrarily closely, but you can never attain it in reality. In this lab we will examine and test consequences of the 0th law and the 1st law. One example of the combination of the zeroth and first law is this problem: Calculate the final equilibrium temperature when a a 0.1 k. block of copper at 5 0 C is dropped into 1.0 kg of water at 80 0 C : English Math The internal energy of the system (block + water) should remain the same since no energy or work is done on (or by) the system. U system = U block  U water = 0 The change in internal energy of the block should equal negative the change in internal energy of the water. U block = − U water Since there is no work done on (or by) the block or water, the heat gained by the block is equal to the heat lost by the water. Q block = − Q water The heat gained (or lost) by either is the product of its mass, specific heat, and change in temperature. m
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This note was uploaded on 02/29/2012 for the course PHYS 227 taught by Professor Rabe during the Fall '08 term at Rutgers.

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thermo - Thermodynamics Objective: To investigate the...

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