lecture 23 - Fourier 2

lecture 23 - Fourier 2 - Announcements 2/28/11 Prayer My...

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Unformatted text preview: Announcements 2/28/11 Prayer My office hours this week: I’ll likely be in my lab, room U130, just down the hall from normal office hour location. Find me there. Exam 2 starts on Saturday Exam review session, results of voting: a. Friday 3:30 – 5 pm. Room: C261 Next week: I’ll be out of town on Mon. You’ll have Dr. Gus Hart as a substitute. Summary of last time 1 ( ) L a f x dx L = ∫ 2 2 ( )cos L n nx a f x dx L L π = ÷ ∫ 2 2 ( )sin L n nx b f x dx L L π = ÷ ∫ 1 1 2 2 ( ) cos sin n n n n nx nx f x a a b L L π π ∞ ∞ = = = + + ÷ ÷ ∑ ∑ The series How to find the coefficients Fourier Transform (review) Do the transform (or have a computer do it) Answer from computer: “There are several components at different values of k; all are multiples of k=0.01. k = 0.01: amplitude = 0 k = 0.02: amplitude = 0 … … k = 0.90: amplitude = 1 k = 0.91: amplitude = 1 k = 0.92: amplitude = 1 …” 600 400 200 200 400 600 20 10 10 20 Cos 0.9x Cos 0.91x Cos 0.92x Cos 0.93x Cos 0.94x Cos 0.95x Cos 0.96x Cos 0.97x Cos 0.98x Cos 0.99x Cos 1.x...
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lecture 23 - Fourier 2 - Announcements 2/28/11 Prayer My...

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