This preview shows pages 1–2. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: y = x 3 2 x + 1 at x = 2 The slope of the tangent line at any point is the derivative at that point Solution: y ' = 3 x 2 2 At x = 2, we need to find m and y : x = 2 then m =y ' (2) = 3(2) 2 2 = 10 Now we want to find the equation of the line that passes the point ( x = 2, y = 5) with m = 10 x = 2 then y (2) = (2) 3 2(2) + 1= 5 y = mx + b 5 = (10)(2) + b15 = b The equation of the tangent line at x = 2 is: y = 10 x  15 5...
View Full
Document
 Fall '09
 MaanOmran
 Derivative, Slope

Click to edit the document details