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Unformatted text preview: y = x 3 2 x + 1 at x = 2 The slope of the tangent line at any point is the derivative at that point Solution: y ' = 3 x 2 2 At x = 2, we need to find m and y : x = 2 then m =y ' (2) = 3(2) 2 2 = 10 Now we want to find the equation of the line that passes the point ( x = 2, y = 5) with m = 10 x = 2 then y (2) = (2) 3 2(2) + 1= 5 y = mx + b 5 = (10)(2) + b15 = b The equation of the tangent line at x = 2 is: y = 10 x  15 5...
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 Fall '09
 MaanOmran
 Derivative, Slope, Want

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