Exam3 - review questions KEY

# Exam3 - review questions KEY - Q1 If the tolerance limits...

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Q1 If the tolerance limits are: 100.00 ± 5, σ = 2 Current process average = 100.5 1.) What is the Cp? _______________________________ 2.) Given the above Cp, what is the probability of acceptance? _____________________ 3.) What is the Cpk? _________________________________ 4.) Given the above Cpk, what is the probability of acceptance? ____________________ 1.) UTL = 105, LTL = 95 C p = (UTL – LTL) / (6 σ ) = (105 –95) / 12 = 0.833. 2.) Probability of acceptance = Pr (95 X 105) with μ =100 and σ =2 = Pr(-2.5 Z 2.5) = 0.9938 – (1 - 0.9938) = 0.9876 3.) C pk = min[( μ – LTL) / (3 σ ), (UTL – μ ) / (3 σ )] = min[(100.5 – 95)/(6), (105 – 100.5)/(6)] = min(0.917, 0.750) = 0.75 4.) Pr of acceptance = Pr (95 X 105) with μ =100.5 and σ = 2 = Pr [(100.5 – 95)/(2) Z (105 – 100.5)/(2)] = Pr (-2.75 Z 2.25) = 0.9878 – (1 – 0.9970) = 0.9848

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.   Q2 Consider the assembly process shown to the right involving two parts X and Y. Times shown in boxes are in seconds per unit . There is one worker each at machines M1, M2, R1, R2 and A1. a.i.1. What is the capacity of the process in units/hour ? Capacities in units per hour: Stage 1: 3600/8 = 450 Stage 2: 3600/30 + 3600/20 =300 Stage 3: 3600/15 = 240 Stage 4: 3600 / 10 = 360. Bottleneck: stage 3. Capacity = 240 units/hr. a.i.2. What is the hourly labor productivity ? Since there are 5 workers, productivity = 240/5 = 48 units per labor hour
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## This note was uploaded on 03/03/2012 for the course MGMT 361 taught by Professor Panwalker during the Spring '10 term at Purdue.

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Exam3 - review questions KEY - Q1 If the tolerance limits...

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