Student version ch2 section 3

Student version ch2 section 3 - 3 Things to consider While...

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Low cost. Better process (low rate of recurrence). Non hospital like atmosphere. Patients with similar ailment. Faster recovery time. Annual checkup. Why Shouldice? Capacity calculations: Where is the bottleneck? About 7000 patients / year. Average stay 3.5 days. Patients admitted on 5 days each week, operations performed on 5 days each week (M-F). 12 doctors on staff. Perform 3 to 4 operations / day. 5 operating rooms, 7 operations scheduled each day in a room. Patients examination takes 15 to 20 minutes, exams sessions are conducted in 6 rooms for 3 hours each day. 89 beds. 3. Things to consider While Watching Shouldice Hospital Mgmt 361 Chapter 2 - Process Analysis 1
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Simplified Shouldice Process Examination Pre-OP:Sedation Operation Post Operation Rest Post Operation Exercises Admission Wake Patients Process Analysis: 1) Plot Flow Chart 2) Determine Bottleneck, Process Measures 3) Look for improvements Mgmt 361 Chapter 2 - Process Analysis 2
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Data Recap: About 7000 patients / year. Average stay 3.5 days. Patients admitted on 5 days each week, (S Th) Operations performed on 5 days each week (M-F). 12 doctors on staff. Perform 3 to 4 operations / day. 5 operating rooms, 7 operations scheduled each day in a room. Patients examination takes 15 to 20 minutes, exams sessions are conducted in 6 rooms for 3 hours each day. 89 beds. Mgmt 361 Chapter 2 - Process Analysis 3
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7000 patients / year 140 patients / week (7000 ÷ 50) Examination room : 15 to 20 min per patient (ave 17.5) {6 rooms * 180 [min /(day * room)] * 5 [days / week] } {17.5 [min / patient]} 308 + [patients / week] Mgmt 361 Chapter 2 - Process Analysis 4 Average stay = 3.5 days (50% leave after 3 days, 50% after 4 days) ((3 + 4) ÷ 2))
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Mgmt 361 Chapter 2 - Process Analysis 5 Operating room: 5 rooms * 7 (operations / (day * room) ) * 5 (days / week) = 175 (operations / week) Doctors: 10 (doctors) * 3.5 (operations/(day * doctor)) * 5 (days/week) = 175 (operations/week) Beds: 89 (beds) * 7 (days/week) / 3.5 ( bed -days per patient) = 178 (patients/week)
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Hospital: 28 patients per day five days per week. Average stay = 3.5 days (no arrival on weekends but discharge can take place). The hospital has 89 beds
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Student version ch2 section 3 - 3 Things to consider While...

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