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Unformatted text preview: EC3070 FINANCIAL DERIVATIVES The Mean Value Theorem Rolles Theorem. If f ( x ) is continuous in the closed interval [ a, b ] and differentiable in the open interval ( a, b ), and if f ( a ) = f ( b ) = 0, then there exists a number c ( a, b ) such that f ( c ) = 0. When it is represented geometrically, this theorem should strike one as obvious; and to prove it formally may seem a waste of time. Nevertheless, in proving it, we can show how visual logic may be converted into verbal or algebraic logic. Some of the more punctilious issues of Mathematical Analysis cannot be represented adequately in diagrams, and it is for this reason that we prefer to rely upon algebraic methods when seeking firm proofs of analytic propositions. To prove Rolles theorem algebraically, we should invoke the result that the function f ( x ) must achieve an upper bound or a lower bound in the interval ( a, b ). Or course, the function might have both an upper and a lower bound in ( a, b ). However, imagine that the function rises above the line in the interval, and that it cuts the line only at the points a, b which are not included in the open interval. Then it has an upper bound but not a lower bound. If the function is horizontal over the interval, then every point in ( a, b ) is both an upper bound and a lower bound. Since, in that, case f ( x ) = 0 for every x ( a, b ) there is nothing to prove. We shall prove the theorem for the case where there is an upper bound in ( a, b ) which corresponds to the point c . Then, by assumption, f ( c ) f ( c + h ) for small values of h > 0 which do not carry us outside the interval. It follows that f ( c +) = lim h 0+ f ( c + h ) f ( c ) h . Here the symbolism associated with the limit indicates that h tends to 0 from above. Now let h be a small negative number such that c + h < c remains in the interval ( a, b ). Then f ( c ) = lim h f ( c + h ) f ( c ) h , where the symbolism associated with the limit indicates that h tends to 0 from below. Now the assumption that f ( x ) is continuous in ( a, b ) implies that f ( c +) = f ( c ); and the only way in which this can be reconciled with the inequalities above is if f ( c ) = 0. This proves the theorem in part. The rest of the proof, which concerns the case where there is a lower bound, follows along the same lines. D.S.G. Pollock: stephen pollock@sigmapi.unet.com THE MEAN VALUE THEOREM The following theorem, which is of prime importance in Mathematical Analysis, represents a generalisation of Rolles theorem and it has a similar visual or geometric interpretation: The Mean Value Theorem. If f ( x ) is continuous in the interval [ a, b ] and differentiable in the open interval ( a, b ), then there exists a point c ( a, b ) such that f ( b ) f ( a ) b a = f ( c ) ....
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This note was uploaded on 03/02/2012 for the course EC 3070 taught by Professor D.s.g.pollock during the Spring '12 term at Queen Mary, University of London.
 Spring '12
 D.S.G.Pollock

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