L20_a - GAUSS'S LAW FOR SYMMETRIC CHARGE DISTRIBUTIONS...

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GAUSS’S LAW FOR SYMMETRIC CHARGE DISTRIBUTIONS (19.10) Recall Gauss’s Law: 0 inside surface closed over e ε q A d E = = Φ r r A d r is a vector normal to surface with magnitude equal to the area of the surface element
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How do we use Gauss’s Law? Two Ways: 0 inside e ε q = Φ o relates flux to charge inside for surface of ANY shape 0 inside surface closed over q A d E = r r o gives a way to calculate E r for SPECIAL cases ± mostly useful if we normal component of E r is constant over part of the surface and can be factored out of the integral
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Using Gauss’s law to calculate Electric Field E r M ust know direction of electric field from symmetry of problem o radial (spherical symmetry) for point charge o radial (cylindrical symmetry) for a long line of charge o uniform for a large flat sheet of charge
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Must choose Gaussian surface that allows us to calculate = Φ surface closed over e A d E r r o Must be able to factor E r out of flux integral in region of space where we
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L20_a - GAUSS'S LAW FOR SYMMETRIC CHARGE DISTRIBUTIONS...

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