drill_set2_sol

drill_set2_sol - Solutions to 5.13 Drill Problems for...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
Solutions to 5.13 Drill Problems for 9/17/03-9/24/03 IR Spectroscopy 1. [ a > b ] because the difference in mass across the C=C double bond is greater in a than in b. 2. [ b > c > a ] because a CO triple bond is stronger than a CO double bond, which is stronger than a CO single bond, and the difference in mass ratios is negligible. In other words, the spring constant is bigger – the spring is tighter! 3. [ a > b ] because Fe is much heavier than C. Put something really heavy on one end of a spring – it then bounces back and forth much more slowly! 4. [ a > b > c ] because a C(sp 3 )-H bond is stronger than a C(sp 2 )-H bond, which is stronger than a C(sp)-H bond. Greater p-character puts electrons further away from the carbon nuclei, giving the C-H bonds more covalent character (and thus strength). 13 C NMR 1. [ a < b < c ] because chemical shift goes down with increasing electron density (shielding). Li is best at stabilizing a positive charge, so the Li-C bond is the most polarized of the
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 03/02/2012 for the course CHEM 512 at MIT.

Page1 / 2

drill_set2_sol - Solutions to 5.13 Drill Problems for...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online