problem03_93

University Physics with Modern Physics with Mastering Physics (11th Edition)

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3.93: a) Taking all units to be in km and h, we have three equations. We know that heading upstream 2 / / = - G w w c v v where w c v / is the speed of the curve relative to water and w G v / is the speed of the water relative to the ground. We know that heading downstream for a time . 5 ) ( , / / = + t v v t G w w c We also know that for the bottle . 3 ) 1 ( / = + t v G w Solving these three equations for
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Unformatted text preview: x, v x v w c G w + = = 2 , / / therefore 5 ) 2 ( = + + t x x or . 5 ) 2 2 ( = + t x Also , x t 1 / 3-= so 5 ) 1 )( 2 2 ( 3 =-+ x x or . 6 2 2 =-+ x x The positive solution is km/h. 5 . 1 / = = G w v x b) . km/h 5 . 3 km/h 2 / = + = w/G w c v v 1...
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This document was uploaded on 02/04/2008.

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