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Unformatted text preview: of equation you may have to solve. (b) Rewrite this to the form13 . 2 = log 10 x . Now take 1013 . 2 = 10 log 10 x = x . Therefore x = 6 . 3096 × 1014 . Note that the calculator notation ( 6.3095E14 ) is unacceptable . (c) Take a natural logarithm of both sides: ln 13 . 2 = ln e x 2 = x 2 . The answer falls out immediately: x = √ ln 13 . 2 = 1 . 6063. (d) Crossmultiply and rearrange: 4 . 3( x + 1) = x. ∴ 3 . 3 x =4 . 3 . ∴ x =1 . 3030 . 1 (e) Again, start by crossmultiplying and rearranging: a ( x + c ) = 2 x 2 + b. ∴ 2 x 2ax + bac = 0 . ∴ x = a ± p a 24(2)( bac ) 2(2) = 1 4 ± a ± p a 28( bac ) ² . 2...
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 Fall '06
 Roussel
 Equations, pH, Quadratic equation, Elementary algebra, Natural logarithm, Logarithm

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