test3s - Chemistry 2740 Spring 2011 Test 3 Solutions 1. (a)...

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Unformatted text preview: Chemistry 2740 Spring 2011 Test 3 Solutions 1. (a) False. A solution containing an ion always also contains a counterion. (b) False. E determines whether a reaction is thermodynamically allowed or not, not E . (c) True. In order for this reaction to occur, we need to break an Fe-C bond, break up the hydroxide ion, transfer its oxygen atom to CO, and make a new bond between the iron atom and the resulting hydride ion. This seems like a lot to do in one step. 2. pH =- log 10 a H + =- log 10 ( H + [H + ] /c ) =- log 10 H + + log 10 ( [H + ] /c ) . error = pH + log 10 ( [H + ] /c ) =- log 10 H + =- log 10 e ln H + . (If you dont know this change of base trick, you can always just calculate H + and then plug the result back into the previous step.) ln H + = ln =- A | z + z- | ( T )- 3 / 2 p I c . error = log 10 e A | z + z- | ( T )- 3 / 2 p I c ....
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This note was uploaded on 03/03/2012 for the course CHEM 2740 taught by Professor Roussel during the Fall '07 term at Lethbridge College.

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test3s - Chemistry 2740 Spring 2011 Test 3 Solutions 1. (a)...

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