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Exam 3 - S09-1 - Math 1260 Exam 3 Solutions Spring 2009 1...

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Math 1260 Exam 3 Solutions – Spring 2009 1.) 195 + 180 2073 0 . 171 2.) f 00 (2) = P 00 4 (2) = 0 3.) Immediately after the injection on the first day, the patient’s body contains A mg of the drug. Immediately after the injection on the second day, the amount of the drug is A mg, which was just injected, plus Ae - 0 . 2 mg remaining from the amount injected on the first day. Thus, immediateley after injection on the second day, the patient’s body contains A + Ae - 0 . 2 mg of the drug. Immediately after the injection on the third day, the amount of the drug is A mg, which was just injected, plus Ae - 0 . 2 mg remaining from the amount injected on the second day, plus Ae - 0 . 4 mg remaining from the amount injected on the first day. Thus, immediateley after injection on the third day, the patient’s body contains A + Ae - 0 . 2 + A ( e - 0 . 2 ) 2 mg of the drug. In a similar way, we see that on the n -th day, the patient’s body contains A + Ae - 0 . 2 + A ( e - 0 . 2 ) 2 + · · · + A ( e - 0 . 2 ) n - 1 = n X k =1 A ( e - 0 . 2 ) k - 1 mg of the drug.
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