forces - Those forces are van der Waals forces. In ClF, the...

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Solutions to Additional Intermolecular Forces (Liquids) Problems 1. The molecules are CH 3 Br, CH 3 -O-CH 3 and H 3 C-OH. Br does not form hydrogen bonds. Methanol (H 3 C-OH) has both an electronegative O atom and the required OH bond. It will form hydrogen bonds. Dimethyl ether (CH 3 -O-CH 3 ) does have an O atom, but not an OH bond. It will not form hydrogen bonds. 2. ClF is polar, but since the electronegativity of Cl and F are similar, the bond is still essentially covalent. The boiling point is the temperature at which the forces holding the molecules together (as a liquid) are overcome.
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Unformatted text preview: Those forces are van der Waals forces. In ClF, the magnitude of the forces is the average of those for F 2 and Cl 2 . Therefore, the boiling point of ClF is lower than that of Cl 2 . 3. Of the three molecules shown, H 2 O 2 and H 2 SO 4 meet the hydrogen bonding criteria. 4. Solid H 2 O (ice) has two hydrogen bonds per molecule, while HF has only one. Even though the HF hydrogen bonds are stronger, the number of hydrogen bonds in ice is greater and so is the energy needed to melt ice (break the hydrogen bonds)....
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forces - Those forces are van der Waals forces. In ClF, the...

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