Unformatted text preview: s = v t + ½ at 2 = 0 + 0.5(3 m/s 2 )(4.5 s) 2 = 30.375 m down the incline. (A) v = 13.5 2 + 10 2 = 16.8 m/s θ = tan1 (10/13.5) = 36.5 ° Answer : 16.8 m/s at 31.5 ° (B) 30.375 m First find time to hit ground: 28.163 m Set y = y + v y t − ½ gt 2 = 0 t = 1.40 s v x = 16.8cos31.5 ° v y = − 16.8sin31.5 ° 21.837 m 11.379 m 8.82 m x = v x t = (16.8cos31.5 ° )(1.40 s) = 20.0 m Answer : 11.2 from the base of the incline 50 m 68 ° 22 ° θ 13.5 m/s 10 m/s 68 ° y 0...
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 Fall '08
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