solns1B - y = v y gt = 28.05 m/s v = v x 2 + v y 2 = 28.4...

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EXAM 1B SOLUTIONS – PHYS 15200 Page 1 of 1 Part I. Multiple Choice Questions [2 pts each] 1) A 2) C 3) C 4) A 5) D Part II. Word Problems [30 pts each] 1) (A) a ( t ) = 36 12 t = 0 t = 3 s, so v (3 s) = 54 m/s = maximum (B) F Net = ma (2 s) = 120 N 2) v 0 y = 1.5 m/s; v x = 4.5 m/s; y 0 = 40 m (A) Set y = y 0 + v 0 y t 1 2 gt 2 equal to zero, solve for t t = 3.01 s (B) Compute v
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Unformatted text preview: y = v y gt = 28.05 m/s v = v x 2 + v y 2 = 28.4 m/s 3) (A) Acceleration down ramp = g (sin cos ) = 1.05 m/s 2 Use v 2 = v 2 + 2 as = 2 + 2(1.05)(10) v = 4.58 m/s at bottom of ramp (B) Acceleration along floor = g = 2.45 m/s 2 Use v 2 = v 2 + 2 as s = 4.28 m...
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