solns3B-1

solns3B-1 - (C) Angular momentum conservation: (1/3 ML 2 )...

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EXAM 3B SOLUTIONS Part I – Multiple Choice Questions 1) B 2) D 3) A 4) D 5) B Part II – Word Problems 1) ω 0 = 5000 rpm = 500 π /3 rad/s; = 440 rpm = 44 π /3 rad/s (A) α = 0 t = -133 rad/s 2 (B) θ = 1 2 ( 0 + ) t = 163 rev (C) I = Σ τ / = (-58 N-m) / (-133 rad/s 2 ) = 0.437 kg-m 2 2) (A) I = 1/3 ML 2 + mr 2 = 1.28 kg-m 2 (B) Energy conservation: Mg ( L /2) = ½ (1/3 ML 2 ) 0 2 0 = 4.95 rad/s
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Unformatted text preview: (C) Angular momentum conservation: (1/3 ML 2 ) = I = 3.71 rad/s 3) (A) hinge = F (0.8 L ) Mg (0.4 L ) 3 Mg (8 L /15) = 0 F = 2.5 Mg (B) F y = N hinge + F Mg 3 Mg = 0 N hinge = 1.5 Mg N hinge F 3 Mg Mg 0.6 L 8 L /15 0.4 L...
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This note was uploaded on 03/03/2012 for the course PHYS 152 taught by Professor Button during the Fall '08 term at IUPUI.

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