Unformatted text preview: 10.24; 10.24; 4.76. The test statistic value is: ) 3 ( 2 X = (5 – 4.76) 2 /4.76 + (12 – 10.24) 2 /10.24 + (9 – 10.24) 2 /10.24 + (4 – 4.76) 2 /4.76 = 0.586. Do not reject H . [Note that two expected counts are slightly below 5. However, other partitions also lead to nonrejection of the null hypothesis.] 50 The test statistic now has 2 fewer degrees of freedom: df = 4 – 3 = 1. We have: x = 11.21 and s = 2.71. Forming a partition using z = 0.44 and z = –0.44 leads to: . 88 . 2 082 . 24 . 86 . 7 . 1 ) 1 ( 2 = + + + = X At α = 0.05, we cannot reject H . 58 X 2 = 4.23 df = 3 Do not reject H . 61 X 2 = 24.36 df = 6 Reject H . 62 Median = 15 X 2 = 4.159 df = 2 Do not reject H . 141...
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 Spring '10
 Phong
 ChiSquare Test, Normal Distribution, Statistical hypothesis testing, nonparametric methods, observed counts

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