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# lec-31 - Administration Homework 11 Due Tuesday at 5:00 PM...

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Administration I Homework 11 Due Tuesday at 5:00 PM

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CS70: Satish Rao: Lecture 31. Continuous Probability 1. Motivation. 2. Continuous Random Variables. 3. Cumulative Distribution Function. 4. Probability Density Function 5. Expectation and Variance
James Bond. I Escapes from SPECTRE sometime during 1 , 000 mile flight. I Uniformly likely to be at any point along path.

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James Bond. I Escapes from SPECTRE sometime during 1 , 000 mile flight. I Uniformly likely to be at any point along path. What is chance he is at any point along the path?
James Bond. I Escapes from SPECTRE sometime during 1 , 000 mile flight. I Uniformly likely to be at any point along path. What is chance he is at any point along the path? Discrete Setting: Uniorm over Ω = { 1 ,..., 1000 } .

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James Bond. I Escapes from SPECTRE sometime during 1 , 000 mile flight. I Uniformly likely to be at any point along path. What is chance he is at any point along the path? Discrete Setting: Uniorm over Ω = { 1 ,..., 1000 } . Continuous setting: probability at any point in [ 0 , 1000 ] ? Probability at any one of an infinite number of points is ..
James Bond. I Escapes from SPECTRE sometime during 1 , 000 mile flight. I Uniformly likely to be at any point along path. What is chance he is at any point along the path? Discrete Setting: Uniorm over Ω = { 1 ,..., 1000 } . Continuous setting: probability at any point in [ 0 , 1000 ] ? Probability at any one of an infinite number of points is .. ...uh ...

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James Bond. I Escapes from SPECTRE sometime during 1 , 000 mile flight. I Uniformly likely to be at any point along path. What is chance he is at any point along the path? Discrete Setting: Uniorm over Ω = { 1 ,..., 1000 } . Continuous setting: probability at any point in [ 0 , 1000 ] ? Probability at any one of an infinite number of points is .. ...uh ...0?
Continuous Probability: the interval! Consider [ a , b ] [ 0 ,‘ ] (for James, = 1000 . )

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Continuous Probability: the interval! Consider [ a , b ] [ 0 ,‘ ] (for James, = 1000 . ) Let [ a , b ] also denote the event that point is in the interval [ a , b ] .
Continuous Probability: the interval! Consider [ a , b ] [ 0 ,‘ ] (for James, = 1000 . ) Let [ a , b ] also denote the event that point is in the interval [ a , b ] . Pr [[ a , b ]] = length of [ a , b ] length of [ 0 ,‘ ] = b - a = b - a 1000 .

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Continuous Probability: the interval! Consider [ a , b ] [ 0 ,‘ ] (for James, = 1000 . ) Let [ a , b ] also denote the event that point is in the interval [ a , b ] . Pr [[ a , b ]] = length of [ a , b ] length of [ 0 ,‘ ] = b - a = b - a 1000 . Again, [ a , b ] Ω = [ 0 ,‘ ] are events.
Continuous Probability: the interval! Consider [ a , b ] [ 0 ,‘ ] (for James, = 1000 . ) Let [ a , b ] also denote the event that point is in the interval [ a , b ] . Pr [[ a , b ]] = length of [ a , b ] length of [ 0 ,‘ ] = b - a = b - a 1000 . Again, [ a , b ] Ω = [ 0 ,‘ ] are events. Events in this space are unions of intervals.

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Continuous Probability: the interval! Consider [ a , b ] [ 0 ,‘ ] (for James, = 1000 . ) Let [ a , b ] also denote the event that point is in the interval [ a , b ] . Pr [[ a , b ]] = length of [ a , b ] length of [ 0 ,‘ ] = b - a = b - a 1000 .
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lec-31 - Administration Homework 11 Due Tuesday at 5:00 PM...

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