lec-38 - Administration 1. Two Grading schemes. Higher of...

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Unformatted text preview: Administration 1. Two Grading schemes. Higher of two. 2. Homework reconciliation day. Administration 1. Two Grading schemes. Higher of two. 2. Homework reconciliation day. Tuesday 12-3. December 6th. Administration 1. Two Grading schemes. Higher of two. 2. Homework reconciliation day. Tuesday 12-3. December 6th. Will have all old homeworks. Administration 1. Two Grading schemes. Higher of two. 2. Homework reconciliation day. Tuesday 12-3. December 6th. Will have all old homeworks. Location: TBA. Administration 1. Two Grading schemes. Higher of two. 2. Homework reconciliation day. Tuesday 12-3. December 6th. Will have all old homeworks. Location: TBA. waiting on room scheduling. Administration 1. Two Grading schemes. Higher of two. 2. Homework reconciliation day. Tuesday 12-3. December 6th. Will have all old homeworks. Location: TBA. waiting on room scheduling. 3. Watch Piazza for final review session! Extra office hours. Etc. CS70: Satish Rao: Lecture 38. I Undecidability. Barber paradox. Barber announces: Barber paradox. Barber announces: The barber shaves every person who does not shave themselves. Barber paradox. Barber announces: The barber shaves every person who does not shave themselves. Who shaves the barber? Barber paradox. Barber announces: The barber shaves every person who does not shave themselves. Who shaves the barber? Get around paradox? Barber paradox. Barber announces: The barber shaves every person who does not shave themselves. Who shaves the barber? Get around paradox? The barber lies. Russells Paradox. Naive Set Theory: Any definable collection is a set. Russells Paradox. Naive Set Theory: Any definable collection is a set. y x ( x y P ( x )) (1) Russells Paradox. Naive Set Theory: Any definable collection is a set. y x ( x y P ( x )) (1) y is the set of elements that satifies the proposition P ( x ) . Russells Paradox. Naive Set Theory: Any definable collection is a set. y x ( x y P ( x )) (1) y is the set of elements that satifies the proposition P ( x ) . P ( x ) = x 6 x . Russells Paradox. Naive Set Theory: Any definable collection is a set. y x ( x y P ( x )) (1) y is the set of elements that satifies the proposition P ( x ) . P ( x ) = x 6 x . There exists a y that satisfies statement 1 for P ( ) . Russells Paradox. Naive Set Theory: Any definable collection is a set. y x ( x y P ( x )) (1) y is the set of elements that satifies the proposition P ( x ) . P ( x ) = x 6 x . There exists a y that satisfies statement 1 for P ( ) . Take x = y . Russells Paradox. Naive Set Theory: Any definable collection is a set....
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lec-38 - Administration 1. Two Grading schemes. Higher of...

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