{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

geos100spr2012_isostasy

# geos100spr2012_isostasy - 1 Consider a wooden block...

This preview shows pages 1–2. Sign up to view the full content.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 1 Consider a wooden block floating in water, as depicted below: According to Archimedes, “any floating object displaces its own weight of fluid.” That is to say, the weight of the floating object and the weight of the fluid displaced by the object are equal. In the case of our floating wooden block, we can summarize this principle as follows: 2 1 W W (1) where W 1 is the weight of the wood and W 2 is the weight of the displaced water. Weight is defined as gravitational force acting on the mass of an object: Mg W (2) where m is the object’s mass and g is the acceleration due to gravity (9.81 m/s 2 ), which is a constant. Substituting equation 2 into equation 1 gives us: g M g M 2 1 (3) where M 1 is the mass of the wood and M 2 is the mass of the displaced water. Since g is a constant and is on both sides of the equation, we can ignore it and simplify equation 3 as: 2 1 M M (4) Density ( ) is mass per unit volume ( V ), and can be expressed as: V M (5) Rearranging equation 5 to solve for mass, we get: V M (6) Substituting equation 6 into equation 4, we get: 2 2 1 1 V V (7) where 1 and V 1 are the density and volume of the wood, and 2 and V 2 are the density and volume of the displaced water. Volume is the product of the length ( l ), width ( w ), and depth ( d ) of an object: lwd V (8) Substituting equation 8 into equation 7, we get: 2 2 2 2 1 1 1 1 d w l d w l (9) where l 1 , w 1 , and d 1 , are the length, width, and depth of the wood, and...
View Full Document

{[ snackBarMessage ]}

### Page1 / 3

geos100spr2012_isostasy - 1 Consider a wooden block...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online