ECE201Lect-3

# ECE201Lect-3 - Single Loop Circuits(2.3 Single-Node-Pair...

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ECE201 Lect-3 1 Single Loop Circuits (2.3); Single-Node-Pair Circuits (2.4) Dr. Holbert

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ECE201 Lect-3 2 Single Loop Circuit The same current flows through each element of the circuit---the elements are in series. We will consider circuits consisting of voltage sources and resistors.
ECE201 Lect-3 3 Example: Christmas Lights + 120V 228 50 Bulbs Total 228 228 I

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ECE201 Lect-3 4 Solve for I The same current I flows through the source and each light bulb- how do you know this? In terms of I , what is the voltage across each resistor? Make sure you get the polarity right! To solve for I , apply KVL around the loop.
ECE201 Lect-3 5 228 I + 228 I + … + 228 I - 120V = 0 I = 120V/(50 × 228 ) = 10.5mA + 120V 228 228 228 I + 228 I + 228 I 228 I +

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ECE201 Lect-3 6 Some Comments We can solve for the voltage across each light bulb: V = IR = (10.5mA)(228 Ω29 = 2.4V This circuit has one source and several resistors. The current is Source voltage/Sum of resistances (Recall that series resistances sum)
ECE201 Lect-3 7 In General: Single Loop

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ECE201Lect-3 - Single Loop Circuits(2.3 Single-Node-Pair...

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