HW+6+solutions

# HW+6+solutions - Eq.34 p.i60 I:——-—_e d 0"WW DO...

This preview shows pages 1–4. Sign up to view the full content.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Eq.34 p.i60 I:——-—:___e - d 0 "WW. ' DO 7- J VO 1 *thac e R The Tom-l energy dissipa‘red fsfpdt =f o o ()0 dt 2 _. Va RC '70 e _L w— 2. 0 Suppose we have a l micro-Faer capaCH'or‘ charged +0 tOO vol+s. Q 2 CV = 10'” coulombs. One eiecfron charge is 1.6 >4 IO-” coukombs. Ii? to = RC is +he +ime cons+an+, we shall have one eiedron IeFJr ” 1.6xto'” 't — whene/t°=~W—>0F —£-:/BTU|.6XIOIS O This gives t 2 tax 2.3 103.0(6x10’q) = 3‘HLO . 50 1F +he +ime cons+an+ were a: I sec, we'd be down +0 "one efedron“ In a “Hie over halF a minufei Rz . _ ' RI Rin R. + RZ+RR Se‘H'mg Rm " R) . . _ RZR Rm 122% %R we. have R “R, + R1+R Rz—Rﬁ — m2 =0 R. :JR} +4R1Rz The negarive roo+ is do?“ ordinarily ' 2 realizable. We are leEJr wi+h : R :1/R3 + 4:2,}?1 + R. 2 R: Given V Wha+ is V’? Replace +he ladder +0 +he right OF B J by R. Tha‘r won’+ affed any+hing +0 +he leP+ OF B. We now have: C R' The res'lerance befween 4, R2 R C and A is Juer R, as A ‘_ - we know. Eviden’rlyji-hen, I ﬂ}..— ‘ R 1 I %=(R+RR1) =R+2RZ I¥wewanT-\\—:—=-§: we muer have R: R2 Then 2R2 = UR3+4RIR2+ R. (ZRI‘RJZ : R? + H'RrRz QR: : SRIRZ or R2: 2R: To Jrerminafe The ladder dF+er any secﬁon, simply conned on a Singie resisfor O‘F value R. 5 1:5" 2| In reer IO Cm Frame 0? pioTes : . A], i S‘ro‘t‘voH' E ._. __._.._._____.___._ y 0 T Z Gm 234,“ .. _ : 0.5 '1+ K \ \€ _ S’rcgvo cm 20cm 03 : o Lin' \I G0 = OQAO '- Number 0F excess elec+rons on nega+ive ploie 2 36° Eo A0 0.5 x i0 x 20 4W8 “ W * 1.66 X iolo eiec‘rrons Frame F, is moving eas+ (11‘ 0.6 C. In i:F ,+he pia+e5 are moving weer a+ 0.6 C. Their eas+-wes+ dimension is 20W = iecm. NS dimension is unchanged, as is +he ver+icoi separa+ion. The number OF elecirons on “the negaﬁve piafe is The same, 1.66 X io'°. Bu+ CT, and E, I are greoi'erJ by +he Facior a” = ' = 1.25 ._ 2 E _ 3/5 _ 0625 5+a’rvoi‘is ” ‘6 I” 0 — ' Crn Frame F2 is moving upward o+ 0.6 C. In F2, +he piaJre dimensions are 20x iOcm, +he ver+icoi separaﬁon is 2Vi~.62 = L6 cm. The number oF eiec+rons is unchanged. 0'2 =0; and E1: E0 = 0.5 si’ai’voiTs/cm. e: .6 {zizs My 2.8 e=+an'*2f= SioLi" E: ZTFO' E,,=Ei zﬁwo I WIN)”: _ Eil :Ell : YE; E Z 2 E -- Charge befween A and B is some as charge beTween A’ and 5' (7W : UV? O"=1.ioL+3(T Gauss‘s law . ’ S‘HH holds. cp :2ie~45°)= i2.68° Ean’cos a: l.iO‘i3E The Field of +he pro’f’on (If The posi‘f'ion 01C ‘H‘e plan is e/rz 3 fhe Force on Jrhe pion is Ee. F = 2/r2 = 2.3 x 10"5 dyne. The Fn'eld 0F +he pioh (1+ +he posiﬁon 0F +he profon is (|~,62)e/r2 (Eq. :2 wiTh 8 = O) . The Force on “the profon is 0.64 x 2.3 x 15's dyne) _n_gj equal +0 fhe Porce on The pr‘on. There is ' momen+um I'_n me Held and The Field is changing. Only +he fowl momen+um, proTon momenfum + pion' mOmen+um + Field momenTum, is conserved. This 1's no’r a Two a body Sys+6m ! ...
View Full Document

{[ snackBarMessage ]}

### Page1 / 4

HW+6+solutions - Eq.34 p.i60 I:——-—_e d 0"WW DO...

This preview shows document pages 1 - 4. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online