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KirchhoffsLaws7Ed

# KirchhoffsLaws7Ed - KIRCHHOFFCURRENTLAW...

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KIRCHHOFF CURRENT LAW NE OF THE FUNDAMENTAL CONSERVATION PRINCIPLE N ELECTRICAL ENGINEERING CHARGE CANNOT BE CREATED NOR DESTROYED

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NODES, BRANCHES, LOOPS ODE: point where two, or more, elements re joined (e.g., big node 1) OOP: A closed path that never goes wice over a node (e.g., the blue line) RANCH: Component connected between two odes (e.g., component R4) The red path is NOT a loop A NODE CONNECTS SEVERAL COMPONENTS. BUT IT DOES NOT HOLD ANY CHARGE. TOTAL CURRENT FLOWING INTO THE NODE MUST BE EQUAL TO TOTAL CURRENT OUT OF THE NODE (A CONSERVATION OF CHARGE PRINCIPLE) NODE
KIRCHHOFF CURRENT LAW (KCL) UM OF CURRENTS FLOWING INTO A NODE IS QUAL TO SUM OF CURRENTS FLOWING OUT OF HE NODE A 5 A 5 - node   the   of out    flowing negative   the   to   equivalent   is node   a   into    flowing current  LGEBRAIC SUM OF CURRENTS FLOWING INTO A ODE IS ZERO LGEBRAIC SUM OF CURRENT (FLOWING) OUT OF  NODE IS ZERO A GENERALIZED NODE IS ANY PART OF A  CIRCUIT WHERE THERE IS NO ACCUMULATION OF CHARGE ... OR WE CAN MAKE SUPERNODES BY  AGGREGATING NODES 0 : 0 : 7 5 4 2 4 6 1 = + - + - = - + i i i i i i i 3   Leaving 2   Leaving 0 7 6 5 2 1 = + + - - i i i i i : 3   &   2   Adding INTERPRETATION: SUM OF CURRENTS LEAVIN NODES 2&3 IS ZERO VISUALIZATION: WE CAN ENCLOSE NODES 2& INSIDE A SURFACE THAT IS VIEWED AS A GENERALIZED NODE (OR SUPERNODE)

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ROBLEM SOLVING HINT: KCL CAN BE USED O FIND A MISSING CURRENT A 5 A 3 ? = X I a b c d SUM OF CURRENTS INTO NODE IS ZERO 0 ) 3 ( 5 = - + + A I A X A I X 2 - = Which way are charges flowing on branch a-b?
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KirchhoffsLaws7Ed - KIRCHHOFFCURRENTLAW...

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